From mass to molarity
1 mg/mL → 1 mM
For an illustrative molecular weight of 1,000 g/mol: 1 mg/mL is 1 g/L. Dividing by 1,000 g/mol gives 0.001 mol/L, or 1 mM.
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These examples use hypothetical values to explain the arithmetic. They do not specify a product, solvent or research protocol.
1 mg/mL → 1 mM
For an illustrative molecular weight of 1,000 g/mol: 1 mg/mL is 1 g/L. Dividing by 1,000 g/mol gives 0.001 mol/L, or 1 mM.
1 mM × 10 mL → 10 mg
With the same illustrative molecular weight, 0.001 mol/L × 0.01 L × 1,000 g/mol gives 0.01 g, or 10 mg. The volume is the final solution volume.
5 mM → 50 µM
For a final volume of 10 mL, the stock volume is 0.1 mL (100 µL). Bring that aliquot to 10 mL final volume. The calculated diluent volume is 9.9 mL if volumes are additive.
Molar concentration is the amount of substance per litre of final solution. This calculator converts the inputs to grams, litres and mol/L before performing the calculation.
1 mM = 1,000 µM · 1 mL = 1,000 µL · 1 mg/mL = 1 g/L
Method references: R&D Systems molarity calculator and dilution calculator.
Match the molecular weight to the material’s chemical form and the basis of the mass entered. A parent peptide, salt or hydrated form can have a different molecular weight.
HPLC purity is not automatically the proportion of the weighed material represented by the peptide. This tool applies no assay, purity, moisture or counterion correction. Confirm the measurement basis from the relevant specification or analytical report.
Purity and content explainedFor dilution, both concentrations must describe the same solute on the same basis. The calculation assumes conservation of solute. Bring the aliquot to the specified final volume; the separate diluent estimate assumes additive volumes.
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